x^2+144x-216=0

Solution for x^2+144x-216=0 equation:

x^2+144x-216=0

a = 1; b = 144; c = -216;
Δ = b2-4ac
Δ = 1442-4·1·(-216)
Δ = 21600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21600}=\sqrt{3600*6}=\sqrt{3600}*\sqrt{6}=60\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-60\sqrt{6}}{2*1}=\frac{-144-60\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+60\sqrt{6}}{2*1}=\frac{-144+60\sqrt{6}}{2}
$